(A) The chemical reaction between iodine and concentrated nitric acid is given by: $I_2 + 10HNO_3 \to 2HIO_3 + 10NO_2 + 4H_2O$. Here,the product $Y$ i

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(A) The chemical reaction between iodine and concentrated nitric acid is given by: $I_2 + 10HNO_3 \to 2HIO_3 + 10NO_2 + 4H_2O$. Here,the product $Y$ is $HIO_3$ (iodic acid). To find the oxidation state of iodine $(I)$ in $HIO_3$: Let the oxidation state of $I$ be $x$. $1 + x + 3(-2) = 0$ $1 + x - 6 = 0$ $x - 5 = 0$ $x = +5$. Thus,the oxidation state of iodine in $Y$ is $+5$.

Class 11 Chemistry Redox Reactions Oxidation number and Oxidation state

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Iodine reacts with concentrated $HNO_3$ to yield $Y$ along with other products. The oxidation state of iodine in $Y$ is

JEE MAIN 2019 All JEE MAIN

A
$5$
B
$7$
C
$3$
D
$1$

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Redox Reactions

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Oxidation number and Oxidation state

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Iodine reacts with concentrated $HNO_3$ to yield $Y$ along with other products. The oxidation state of iodine in $Y$ is

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