Iodination of a hydrocarbon (C-H rightarrow C | vedclass

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(B) The correct option is $B$.Iodination of a hydrocarbon is a reversible reaction because the $HI$ produced as a byproduct acts as a reducing agent a

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$HIO_3$

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(B) The correct option is $B$.Iodination of a hydrocarbon is a reversible reaction because the $HI$ produced as a byproduct acts as a reducing agent and reduces the alkyl iodide back to the hydrocarbon.To drive the reaction in the forward direction,an oxidizing agent like $HIO_3$ or $HNO_3$ is added to consume $HI$.The reaction is: $5 HI + HIO_3 \rightarrow 3 I_2 + 3 H_2O$.

Iodination of a hydrocarbon $(C-H \rightarrow C-I)$ with molecular iodine is a slow and reversible reaction. However,it can be carried out in the presence of an oxidizing agent such as

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