Initially,a rectangular coil with its length | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The induced e.m.f. in a conductor moving in a magnetic field is given by $\varepsilon = B l v \sin 	heta$,where $l$ is the length of the conducto

Vedclass · Accepted Answer

less than the initial induced e.m.f.

Vedclass · Answer

(B) The induced e.m.f. in a conductor moving in a magnetic field is given by $\varepsilon = B l v \sin 	heta$,where $l$ is the length of the conductor perpendicular to the velocity vector $v$ and the magnetic field $B$.In the initial case,the length of the coil is vertical,so the vertical side of length $L$ is perpendicular to the velocity $v$ (which is horizontal). Thus,the induced e.m.f. is $\varepsilon_1 = B L v$.After rotating the coil by $90^{\circ}$,the length $L$ becomes horizontal (parallel to the velocity $v$). The side that was previously horizontal (width $W$) is now vertical. The induced e.m.f. is now determined by the side perpendicular to the velocity,which is the side of length $W$. Thus,$\varepsilon_2 = B W v$.Since the length $L$ of a rectangular coil is typically greater than its width $W$ $(L > W)$,the new induced e.m.f. $\varepsilon_2$ will be less than the initial induced e.m.f. $\varepsilon_1$.

Similar Questions

$A$ rectangular loop $PQRS$ is being pulled with a constant speed into a uniform transverse magnetic field by a force $F$ (as shown). The $e.m.f.$ induced in side $PS$ and the potential difference between points $P$ and $S$ respectively are (Resistance of the loop $= r$)

$A$ wheel with radial metal spokes $1 \ m$ in length is rotated in a magnetic field of $0.5 \times 10^{-4} \ T$ normal to the plane of the wheel. If the induced emf between the rim and axle is $\pi / 3000 \ V$,then the rotational speed of the wheel in revolutions per minute is

$A$ conducting rod of length $\ell$ moves with a velocity $V$ in a uniform magnetic field $B$ perpendicular to the plane of the rails. $A$ capacitor of capacitance $C$ is connected across the rails as shown. Find the charge on the capacitor due to the induced emf in the rod.

$A$ conducting wire is moving towards the right in a magnetic field $B$. The direction of the induced current $i$ in the wire is shown in the figure. The direction of the magnetic field will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module