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(A) $1$. When $n$ identical capacitors of capacitance $C$ are connected in parallel and charged to potential $V$,the charge on each capacitor is $q =

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Potential difference becomes $n V$ and energy remains the same.

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(A) $1$. When $n$ identical capacitors of capacitance $C$ are connected in parallel and charged to potential $V$,the charge on each capacitor is $q = CV$. The total energy stored is $U_p = n 	imes (1/2)CV^2 = (n/2)CV^2$.$2$. When these capacitors are separated,each capacitor retains its charge $q = CV$.$3$. When these $n$ capacitors are connected in series,the total potential difference across the combination is the sum of the potential differences across each capacitor: $V_{total} = V + V + ... + V$ ($n$ times) $= nV$.$4$. The total energy stored in the series combination is $U_s = n 	imes (1/2)q^2/C = n 	imes (1/2)(CV)^2/C = (n/2)CV^2$.$5$. Since $U_p = U_s$,the total energy remains the same.

Initially $n$ identical capacitors are joined in parallel and are charged to potential $V$. Now they are separated and joined in series. Then

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