Indicate the number of unpaired electrons in:
$(a)$ $P$ $(b)$ $Si$ $(c)$ $Cr$ $(d)$ $Fe$ and $(e)$ $Kr$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Phosphorus $(P):$
Atomic number $= 15$
Electronic configuration: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}$
Number of unpaired electrons $= 3$
$(b)$ Silicon $(Si):$
Atomic number $= 14$
Electronic configuration: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{2}$
Number of unpaired electrons $= 2$
$(c)$ Chromium $(Cr):$
Atomic number $= 24$
Electronic configuration: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{1} 3d^{5}$
Number of unpaired electrons $= 6$
$(d)$ Iron $(Fe):$
Atomic number $= 26$
Electronic configuration: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{6}$
Number of unpaired electrons $= 4$
$(e)$ Krypton $(Kr):$
Atomic number $= 36$
Electronic configuration: $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6}$
Number of unpaired electrons $= 0$

Explore More

Similar Questions

The charge on $As_2S_3$ sol is due to the adsorbed

Seven white balls and three black balls are randomly arranged in a row. The probability that no two black balls are placed adjacently is

The conjugate base of $HBr$ is:

$A$ motor of power $P_0$ is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe $n$ times,the power of the motor is increased to $P_1$. The ratio of $P_1$ to $P_0$ is

Pyruvate, which is formed by the glycolytic catabolism of carbohydrates in the cytosol, after it enters mitochondrial matrix and undergoes $:-$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo