Which of the following statements is incorrec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $A)$ Due to the small size and high charge density of $Be^{2+}$,its polarizing power is high,which leads to the sharing of electrons between $Be$

Vedclass · Accepted Answer

The hybrid state of $Be$ in solid $BeCl_2$ is $sp^2$

Vedclass · Answer

(D) $A)$ Due to the small size and high charge density of $Be^{2+}$,its polarizing power is high,which leads to the sharing of electrons between $Be$ and $Cl$. This gives $BeCl_2$ significant covalent character.$B)$ The $Be$ atom has only $4$ electrons in its valence shell,which does not satisfy the octet rule. Therefore,it is an electron-deficient molecule.$C)$ $BeCl_2$ exists as a polymeric chain in the solid state and can form a dimer in the vapor phase.$D)$ In solid $BeCl_2$,the $Be$ atom is $sp^3$ hybridized (due to coordinate bonding in the polymeric structure),and in the monomeric gaseous state,it is $sp$ hybridized. Thus,the statement that it is $sp^2$ is incorrect.

Which of the following statements is incorrect?

Similar Questions

The $d$-orbital involved in $sp^3d$ hybridisation is

Which of the following hybridisation has maximum $s-$character?

What is the hybridization of the iodine atom in $ICl_2^-$?

In which of the following cases $C-C$ bond length will be highest?

Which molecule has $sp^3$ hybridization of the central atom?

Vedclass Test Series

Exam Paper Generator

Online Exam Module