Which of the following is the incorrect order | vedclass

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(A) In $CF_4$,$CCl_4$,and $CBr_4$,all are tetrahedral with bond angles of $109.5^\circ$. Thus,the order $\alpha > \beta > \gamma$ is incorrect as they

Vedclass · Accepted Answer

$CF_4 > CCl_4 > CBr_4$ (where $\angle XCX$ is the bond angle and $X$ is a halogen atom)

Vedclass · Answer

(A) In $CF_4$,$CCl_4$,and $CBr_4$,all are tetrahedral with bond angles of $109.5^\circ$. Thus,the order $\alpha > \beta > \gamma$ is incorrect as they are equal.In $NCl_3$,$PCl_3$,and $AsCl_3$,the bond angle decreases as the electronegativity of the central atom decreases $(N > P > As)$,so $NCl_3 > PCl_3 > AsCl_3$ is correct.In $SOF_2$,the $S=O$ double bond exerts more repulsion than the $S-F$ single bonds,making $\angle FSO > \angle FSF$ correct.In $NO_2^+$,$NO_2$,and $NO_2^-$,the bond angles are $180^\circ$,$134^\circ$,and $115^\circ$ respectively,so $NO_2^+ > NO_2 > NO_2^-$ is correct.Therefore,option $A$ is the incorrect order.

$A$. Trigonal planar	$I$. $PCl_5$
$B$. Tetrahedral	$II$. $SF_6$
$C$. Trigonal bipyramidal	$III$. $BF_3$
$D$. Octahedral	$IV$. $CCl_4$

Which of the following is the incorrect order of bond angle?

Similar Questions

Which of the following compounds has a central atom with one lone pair of electrons and three bond pairs of electrons?

Match the molecular geometries in List-$I$ with their corresponding molecules in List-$II$:
$A$. Trigonal planar $I$. $PCl_5$
$B$. Tetrahedral $II$. $SF_6$
$C$. Trigonal bipyramidal $III$. $BF_3$
$D$. Octahedral $IV$. $CCl_4$

The correct match for $A, B, C, D$ is:

What are the structures and shapes of $SF_4$ and $ClF_3$?

In the molecule $I_2Cl_6$,choose the $CORRECT$ statement$(s)$.

Which molecule is linear?

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