The incorrect match is:

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Question

(A) Let us analyze each option:$(A)$ The structure shown is $2$-acetoxybenzoic acid,which is commonly known as $	ext{Aspirin}$. This is a correct mat

Vedclass · Accepted Answer

The structure of $2$-acetoxybenzoic acid : $	ext{Aspirin}$

Vedclass · Answer

(A) Let us analyze each option:$(A)$ The structure shown is $2$-acetoxybenzoic acid,which is commonly known as $	ext{Aspirin}$. This is a correct match.$(B)$ The structure $Cl_3C-CH(C_6H_4Cl)_2$ represents $p,p'$-dichlorodiphenyltrichloroethane,commonly known as $	ext{D.D.T.}$ This is a correct match.$(C)$ The formula $H_2N-CO-NH_2$ represents $	ext{Urea}$. This is a correct match.$(D)$ The structure $H_2N-C_6H_4-SO_3H$ represents $p$-aminobenzenesulphonic acid,which is $	ext{Sulphanilic acid}$. This is a correct match.Wait,re-evaluating the provided image for option $(A)$: The image shows a benzene ring with an acetoxy group $(-O-CO-CH_3)$ and an aldehyde group $(-CHO)$ at the ortho position. This is $2$-acetoxybenzaldehyde,not $	ext{Aspirin}$ ($2$-acetoxybenzoic acid). Therefore,option $(A)$ is the incorrect match.

List-$I$ (Chemical Reaction)	List-$II$ (Reagent used)
$(a)$ $CH_{3}COOCH_{2}CH_{3} \rightarrow CH_{3}CH_{2}OH$	$(i)$ $CH_{3}MgBr / H_{3}O^{+}$ ($1$ equivalent)
$(b)$ $CH_{3}COOCH_{3} \rightarrow CH_{3}CHO$	$(ii)$ $H_{2}SO_{4} / H_{2}O$
$(c)$ $CH_{3}C \equiv N \rightarrow CH_{3}CHO$	$(iii)$ $DIBAL-H / H_{2}O$
$(d)$ $CH_{3}C \equiv N \rightarrow CH_{3}COCH_{3}$	$(iv)$ $SnCl_{2}, HCl / H_{2}O$

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