(B) For coherent sources,the intensity at the midpoint (where path difference is zero) is given by constructive interference:$I_{1} = (A + A)^{2} = (2

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(B) For coherent sources,the intensity at the midpoint (where path difference is zero) is given by constructive interference:$I_{1} = (A + A)^{2} = (2A)^{2} = 4A^{2}$For incoherent sources,interference does not occur,and the intensities simply add up:$I_{2} = A^{2} + A^{2} = 2A^{2}$The ratio of the intensity in the first case to the second case is:$\frac{I_{1}}{I_{2}} = \frac{4A^{2}}{2A^{2}} = \frac{2}{1}$Therefore,the ratio is $2:1$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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In Young's double slit experiment,the two slits act as coherent sources of equal amplitude $A$ and wavelength $\lambda$. In another experiment with the same setup,the two slits are sources of equal amplitude $A$ and wavelength $\lambda$ but are incoherent. The ratio of the intensity of light at the midpoint of the screen in the first case to that in the second case is:

A
$1:1$
B
$2:1$
C
$4:1$
D
none of these

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Wave Optics

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Young's Double Slit Experiment (YDSE)

In a Young's double slit experiment, the slits are separated by $0.3 \, mm$ and the screen is $1.5 \, m$ away from the plane of slits. The distance between the fourth bright fringes on both sides of the central bright fringe is $2.4 \, cm$. The frequency of light used is $.......... \times 10^{14} \, Hz$.

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Assertion: In Young's experiment,the fringe width for dark fringes is different from that for bright fringes.
Reason: In Young's double slit experiment,if the fringes are performed with a source of white light,then only black and bright fringes are observed.

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If the distance between the first maxima and the fifth minima of a double slit pattern is $7\,mm$ and the slits are separated by $0.15\,mm$ with the screen $50\,cm$ from the slits,then find the wavelength of the light used in $nm$.

Medium

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In a Young's double-slit experiment,the slit separation is $0.589 \, mm$ using sodium light. What is the angular separation between the third maximum and the central maximum? $(\lambda = 589 \, nm)$

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In Young's double-slit experiment,the distance between the two slits is $0.2 \, mm$ and the screen is $200 \, cm$ away from the slits. If the wavelength of light used is $5000 \, \mathring{A}$,find the distance of the third bright fringe from the central bright fringe in $cm$.

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Assertion: In Young's experiment,the fringe width for dark fringes is different from that for bright fringes.Reason: In Young's double slit experiment,if the fringes are performed with a source of white light,then only black and bright fringes are observed.

If the distance between the first maxima and the fifth minima of a double slit pattern is $7\,mm$ and the slits are separated by $0.15\,mm$ with the screen $50\,cm$ from the slits,then find the wavelength of the light used in $nm$.

In a Young's double-slit experiment,the slit separation is $0.589 \, mm$ using sodium light. What is the angular separation between the third maximum and the central maximum? $(\lambda = 589 \, nm)$

In Young's double-slit experiment,the distance between the two slits is $0.2 \, mm$ and the screen is $200 \, cm$ away from the slits. If the wavelength of light used is $5000 \, \mathring{A}$,find the distance of the third bright fringe from the central bright fringe in $cm$.

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Assertion: In Young's experiment,the fringe width for dark fringes is different from that for bright fringes.
Reason: In Young's double slit experiment,if the fringes are performed with a source of white light,then only black and bright fringes are observed.