In Wilkinson's catalyst,the hybridization of the central metal ion and its shape are respectively:

  • A
    $sp^3d,$ trigonal bipyramidal
  • B
    $d^2sp^3,$ octahedral
  • C
    $dsp^2,$ square planar
  • D
    $sp^3,$ tetrahedral

Explore More

Similar Questions

Which statement is correct?

Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory:
$(i)$ $[Fe(CN)_6]^{4-}$
$(ii)$ $[FeF_6]^{3-}$
$(iii)$ $[Co(C_2O_4)_3]^{3-}$
$(iv)$ $[CoF_6]^{3-}$

$NiCl_2\{P(C_2H_5)_2(C_6H_5)\}_2$ exhibits temperature-dependent magnetic behaviour (paramagnetic/diamagnetic). The coordination geometries of $Ni^{2+}$ in the paramagnetic and diamagnetic states are respectively

Match the hybridisation in Column $I$ with the complexes in Column $II$. The options represent the matches for $(A), (B), (C), (D)$ respectively.
Column $I$Column $II$
$(A)$ $sp^3$$(i)$ $[Co(NH_3)_6]^{3+}$
$(B)$ $dsp^2$$(ii)$ $[Ni(CO)_4]$
$(C)$ $sp^3d^2$$(iii)$ $[Pt(NH_3)_2Cl_2]$
$(D)$ $d^2sp^3$$(iv)$ $[CoF_6]^{3-}$
$(v)$ $[Fe(CO)_5]$

Cobalt chloride when dissolved in water forms a pink-colored complex $X$ which has an octahedral geometry. This solution,upon treatment with concentrated $HCl$,forms a deep blue complex $Y$ which has a $Z$ geometry. $X$,$Y$,and $Z$,respectively,are:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo