(A) $1$. In $I_3^{-}$,the central $I$ atom has $3$ lone pairs and $2$ bond pairs,resulting in $sp^3d$ hybridisation and a linear shape.$2$. In $BeCl_2

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(A) $1$. In $I_3^{-}$,the central $I$ atom has $3$ lone pairs and $2$ bond pairs,resulting in $sp^3d$ hybridisation and a linear shape.$2$. In $BeCl_2$,the central $Be$ atom has $0$ lone pairs and $2$ bond pairs,resulting in $sp$ hybridisation and a linear shape.$3$. Both species have a linear shape,but their hybridisation states ($sp^3d$ vs $sp$) are different.$4$. Therefore,the pair $I_3^{-}$ and $BeCl_2$ satisfies the given condition.

Class 11 Chemistry Chemical Bonding and Molecular Structure Hybridisation

Medium

In which one of the following pairs do the two species have identical shape,but differ in hybridisation?

AP EAMCET 2015 All AP EAMCET

A
$I_3^{-}, BeCl_2$
B
$NH_3, BF_3$
C
$XeF_2, I_3^{-}$
D
$NH_4^{+}, SF_4$

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Class 11

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Chapter

Chemical Bonding and Molecular Structure

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Hybridisation

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$LIST$-$I$ (Hybridization)	$LIST$-$II$ (Orientation in Space)
$A$. $sp^3$	$I$. Trigonal bipyramidal
$B$. $dsp^2$	$II$. Octahedral
$C$. $sp^3 d$	$III$. Tetrahedral
$D$. $sp^3 d^2$	$IV$. Square planar

In which one of the following pairs do the two species have identical shape,but differ in hybridisation?

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Match List-$I$ with List-$II$ :

$LIST$-$I$ (Hybridization) $LIST$-$II$ (Orientation in Space)

$A$. $sp^3$ $I$. Trigonal bipyramidal

$B$. $dsp^2$ $II$. Octahedral

$C$. $sp^3 d$ $III$. Tetrahedral

$D$. $sp^3 d^2$ $IV$. Square planar

Choose the correct answer from the options given below :