In which of the following reactions is an anti-Markovnikov product formed?

  • A
    $CF_3CH = CH_2 \xrightarrow{HCl}$
  • B
    $ClCH = CH_2 \xrightarrow{HCl}$
  • C
    $CH_3OCH = CH_2 \xrightarrow{HCl}$
  • D
    None of these

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Which of the following rules applies in the reaction:
$CH_3CHBrCH_2CH_3 \xrightarrow{alc. KOH}$
$(i)$ $CH_3CH = CHCH_3$ (major product)
$(ii)$ $CH_2 = CHCH_2CH_3$ (minor product)

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