In which of the following processes,the bond | vedclass

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Question

(A) The bond order and magnetic character are determined using Molecular Orbital Theory $(MOT)$.$1$. For $NO$ ($15$ electrons): Bond order = $(10-5)/2

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$NO 	o NO^{+}$

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(A) The bond order and magnetic character are determined using Molecular Orbital Theory $(MOT)$.$1$. For $NO$ ($15$ electrons): Bond order = $(10-5)/2 = 2.5$. It has one unpaired electron,so it is paramagnetic.$2$. For $NO^{+}$ ($14$ electrons): Bond order = $(10-4)/2 = 3.0$. All electrons are paired,so it is diamagnetic.$3$. In the process $NO 	o NO^{+}$,the bond order increases from $2.5$ to $3.0$ and the character changes from paramagnetic to diamagnetic.$4$. For $N_2 	o N_2^{+}$,bond order decreases $(3.0 	o 2.5)$.$5$. For $O_2 	o O_2^{+}$,bond order increases $(2.0 	o 2.5)$,but it remains paramagnetic.$6$. For $O_2 	o O_2^{2-}$,bond order decreases $(2.0 	o 1.0)$.

In which of the following processes,the bond order has increased and paramagnetic character has changed to diamagnetic?

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