In which of the following pairs does the firs | vedclass

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(B) $SO_2$ bleaches flowers by reduction:$2H_2O + SO_2 	o H_2SO_4 + 2[H]$$2[H] + 	ext{Coloured flower} \xrightarrow{	ext{Reduction}} 	ext{Colourle

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$SO_2$ and $Cl_2$

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(B) $SO_2$ bleaches flowers by reduction:$2H_2O + SO_2 	o H_2SO_4 + 2[H]$$2[H] + 	ext{Coloured flower} \xrightarrow{	ext{Reduction}} 	ext{Colourless reduced flower}$$Cl_2$ bleaches flowers by oxidation:$Cl_2 + H_2O 	o 2HCl + [O]$$[O] + 	ext{Coloured flower} \xrightarrow{	ext{Oxidation}} 	ext{Colourless oxidised flower}$Therefore,the correct pair is $SO_2$ and $Cl_2$.

In which of the following pairs does the first gas bleach flowers by reduction while the second gas does so by oxidation?

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