In which of the following molecules is the N | vedclass

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(C) $1$. In the Nitronium ion $(NO_2^+)$,the $N$ atom is $sp$ hybridized (linear geometry).$2$. In the Nitrate ion $(NO_3^-)$,the $N$ atom is $sp^2$ h

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Trisilylamine $(N(SiH_3)_3)$

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(C) $1$. In the Nitronium ion $(NO_2^+)$,the $N$ atom is $sp$ hybridized (linear geometry).$2$. In the Nitrate ion $(NO_3^-)$,the $N$ atom is $sp^2$ hybridized (trigonal planar geometry).$3$. In Trisilylamine $(N(SiH_3)_3)$,the $N$ atom is $sp^3$ hybridized due to the back-bonding of the lone pair into the empty $d$-orbitals of $Si$,resulting in a planar geometry,but the hybridization state is considered $sp^3$.$4$. In Borazine $(B_3N_3H_6)$,the $N$ atoms are $sp^2$ hybridized as it is an aromatic ring system.$5$. Therefore,the $N$ atom in Trisilylamine is not $sp^2$ hybridized.

In which of the following molecules is the $N$ atom not $sp^2$ hybridized?

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