In which of the following is the keto form mo | vedclass

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(D) The keto-enol tautomerism equilibrium depends on the stability of the keto and enol forms. $(a)$ Cyclobutane$-1,2-$dione: The enol form would be a

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All of these

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(D) The keto-enol tautomerism equilibrium depends on the stability of the keto and enol forms. $(a)$ Cyclobutane$-1,2-$dione: The enol form would be anti-aromatic,which is highly unstable. Thus,the keto form is much more stable. $(b)$ $2-$tert-butylcyclohexane$-1,3-$dione: The enol form experiences a severe steric clash between the bulky tert-butyl group and the hydroxyl group,making the keto form more stable. $(c)$ Bicyclo[$2.2$.$1$]heptane$-2,5-$dione: The formation of the enol form would require a double bond at the bridgehead position,which violates Bredt's rule. Therefore,the keto form is more stable. Since all three cases favor the keto form,the correct answer is $(D)$.

$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

In which of the following is the keto form more dominating than the enol form?

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