Which of the following represents the correct increasing order of crystal field splitting energy?
- A$[CrCl_6]^{4-} < [Cr(H_2O)_6]^{2+} < [Cr(NH_3)_6]^{2+} < [Cr(CN)_6]^{4-}$
- B$[CrCl_6]^{4-} > [Cr(H_2O)_6]^{2+} > [Cr(NH_3)_6]^{2+} > [Cr(CN)_6]^{4-}$
- C$[Cr(H_2O)_6]^{2+} > [CrCl_6]^{4-} > [Cr(NH_3)_6]^{2+} > [Cr(CN)_6]^{4-}$
- DNone of these
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Similar Questions
The crystal field theory is successful in explaining which of the following?
$I.$ Ligands as point charges;
$II.$ Formation and structures of complexes.
$III.$ Colour;
$IV.$ Magnetic properties;
$V.$ Covalent character of metal-ligand bonding.
$I.$ Ligands as point charges;
$II.$ Formation and structures of complexes.
$III.$ Colour;
$IV.$ Magnetic properties;
$V.$ Covalent character of metal-ligand bonding.
Crystal field splitting energies for octahedral $(\Delta_0)$ and tetrahedral $(\Delta_t)$ geometries caused by the same ligands are related through the expression
$[Pd(F)(Cl)(Br)(I)]^{2-}$ has $n$ number of geometrical isomers. Then,the spin-only magnetic moment and crystal field stabilisation energy $[CFSE]$ of $[Fe(CN)_6]^{n-6}$ are
[Note : Ignore the pairing energy]
[Note : Ignore the pairing energy]
The number of unpaired $d$-electrons in $[Co(H_2O)_6]^{3+}$ is $\qquad$
Calculate the crystal field stabilization energy $(CFSE)$ in $[Co(CN)_6]^{3-}$.
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