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(B) To determine the number of unpaired electrons,we analyze the electronic configuration of the central metal ion in each complex:$1$. In $[Cr(NH_3)_

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$[Co(H_2O)_6]^{3+}$

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(B) To determine the number of unpaired electrons,we analyze the electronic configuration of the central metal ion in each complex:$1$. In $[Cr(NH_3)_6]^{3+}$,$Cr$ is in the $+3$ oxidation state. The configuration of $Cr^{3+}$ is $[Ar]3d^3$. Since $NH_3$ is a strong field ligand,but $d^3$ configuration has no choice but to have $3$ unpaired electrons in the $t_{2g}$ orbitals.$2$. In $[Co(H_2O)_6]^{3+}$,$Co$ is in the $+3$ oxidation state. The configuration of $Co^{3+}$ is $[Ar]3d^6$. $H_2O$ is a weak field ligand,so the electrons remain unpaired in the $t_{2g}$ and $e_g$ orbitals,resulting in $4$ unpaired electrons.$3$. In $[Zn(H_2O)_4]^{2+}$,$Zn$ is in the $+2$ oxidation state. The configuration of $Zn^{2+}$ is $[Ar]3d^{10}$. There are $0$ unpaired electrons.$4$. In $[Ni(CN)_4]^{2-}$,$Ni$ is in the $+2$ oxidation state. The configuration of $Ni^{2+}$ is $[Ar]3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $0$ unpaired electrons.Comparing the values,$[Co(H_2O)_6]^{3+}$ has the maximum number of unpaired electrons $(4)$.

In which of the following compounds does the central metal atom have the maximum number of unpaired $e^-$?

Similar Questions

The magnetic moments of the following,arranged in decreasing order,will be:-
$(i)$ $Co^{3+}$ (Octahedral complex with a strong field ligand)
$(ii)$ $Co^{3+}$ (Octahedral complex with a weak field ligand like $F^{-}$)
$(iii)$ $Co^{2+}$ (Tetrahedral complex)
$(iv)$ $Co^{2+}$ (Square planar complex)

Which of the following will show optical isomerism?
$I$. $\text{Cis}-[Co(NH_3)_2(en)_2]^{3+}$
$II$. $\text{Trans}-[IrCl_2(C_2O_4)_2]^{3-}$
$III$. $[Rh(en)_3]^{3+}$
$IV$. $\text{Cis}-[Ir(H_2O)_3Cl_3]$

The correct order of the spin-only magnetic moments of the following complexes is
$(I) [Cr(H_2O)_6]Br_2$
$(II) Na_4[Fe(CN)_6]$
$(III) Na_3[Fe(C_2O_4)_3] (\Delta_0 > P)$
$(IV) (Et_4N)_2[CoCl_4]$

Which of the following complex compounds will exhibit highest paramagnetic behaviour? (At. No. $Ti = 22$,$Cr = 24$,$Co = 27$,$Zn = 30$)

Total number of relatively more stable isomer$(s)$ possible for octahedral complex $[Cu(en)_2(SCN)_2]$ will be $.........$

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