In which case does the heterolysis of the car | vedclass

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(B) The stability of a carbocation is determined by factors like resonance,inductive effect,and hyperconjugation. In the case of $2$-chlorotetrahydrop

Vedclass · Accepted Answer

$2-$chlorotetrahydropyran

Vedclass · Answer

(B) The stability of a carbocation is determined by factors like resonance,inductive effect,and hyperconjugation. In the case of $2$-chlorotetrahydropyran,the heterolysis of the $C-Cl$ bond generates a carbocation adjacent to an oxygen atom. The lone pair of electrons on the oxygen atom can delocalize into the vacant $p$-orbital of the carbocation,forming an oxocarbenium ion. This structure is highly stable because every atom,including the carbon,achieves a complete octet configuration. Therefore,$2$-chlorotetrahydropyran forms the most stable carbocation among the given options.

In which case does the heterolysis of the carbon-chlorine bond lead to the most stable carbocation?

Similar Questions

Which of the following is the most stable carbanion?

Assertion : Carbanions like ammonia have pyramidal shape.
Reason : The carbon atom carrying negative charge has an octet of electrons.

Which of the following options given below is incorrect?

The shape of a carbocation is:

The order of decreasing stability of the carbanions is:
$1.$ $(CH_3)_3C^-$
$2.$ $(CH_3)_2CH^-$
$3.$ $CH_3CH_2^-$
$4.$ $C_6H_5CH_2^-$

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