In vapour phase refining,metal A is purified | vedclass

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(C) $1$. Van Arkel method is used for the purification of metals like $Zr$ (Zirconium) and $Ti$ (Titanium). In this process,the crude metal is heated

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$Zr, Ni$

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(C) $1$. Van Arkel method is used for the purification of metals like $Zr$ (Zirconium) and $Ti$ (Titanium). In this process,the crude metal is heated in an evacuated vessel with iodine to form a volatile metal iodide,which is then decomposed on a tungsten filament at high temperature to obtain pure metal.$2$. Mond's process is specifically used for the purification of $Ni$ (Nickel). In this process,impure nickel is heated in a stream of carbon monoxide to form volatile nickel tetracarbonyl,$Ni(CO)_4$,which is then decomposed at higher temperatures to yield pure nickel.$3$. Therefore,$A$ can be $Zr$ or $Ti$,and $B$ is $Ni$. Comparing with the options,$Zr$ and $Ni$ is a valid pair for $A$ and $B$ respectively.

Column-$I$	Column-$II$
$(a)$ Boron	$(i)$ Van Arkel method
$(b)$ Tin	$(ii)$ Mond's process
$(c)$ Zirconium	$(iii)$ Liquation
$(d)$ Nickel	$(iv)$ Zone refining

In vapour phase refining,metal $A$ is purified by Van Arkel method and metal $B$ is purified by Mond's process. $A$ and $B$ are respectively:

Similar Questions

Which method is used to obtain ultra-pure copper?

Which method of purification is represented by the equation
$Ti + 2I_2$ (Impure) $\xrightarrow{500 \ K} TiI_4$ $\xrightarrow{1675 \ K} Ti + 2I_2$ (Pure)

Which of the following properties of pure metal makes it more useful than the corresponding alloy?

Assertion : Lead,tin and bismuth are purified by liquation method.
Reason : Lead,tin and bismuth have low $m.p.$ as compared to impurities.

Match the elements in Column-$I$ with methods of purification in Column-$II$.

Column-$I$ Column-$II$

$(a)$ Boron $(i)$ Van Arkel method

$(b)$ Tin $(ii)$ Mond's process

$(c)$ Zirconium $(iii)$ Liquation

$(d)$ Nickel $(iv)$ Zone refining

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