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(C) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes,the masses of sub

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$3$

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(C) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes,the masses of substances deposited are proportional to their equivalent weights: $\frac{m_{Ag}}{m_{Au}} = \frac{E_{Ag}}{E_{Au}}$.Given $m_{Ag} = 2.15 \ g$,$m_{Au} = 1.31 \ g$,and $E_{Ag} = \frac{107.9}{1} = 107.9$.Substituting the values: $\frac{2.15}{1.31} = \frac{107.9}{E_{Au}}$.$E_{Au} = \frac{107.9 	imes 1.31}{2.15} \approx 65.7$.Since $	ext{Equivalent weight} = \frac{	ext{Atomic mass}}{	ext{Valency}}$,we have $	ext{Valency} = \frac{197}{65.7} \approx 3$.

In two separate experiments,the same quantity of electricity was passed through silver and gold solutions. The amounts of $Ag$ and $Au$ deposited are $2.15 \ g$ and $1.31 \ g$,respectively. The valency of gold is [Atomic mass of $Ag = 107.9$; $Au = 197$].

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