In the two elements,{ }_{Z_1} A^{M_1} and { } | vedclass

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(A) Given,${ }_{Z_1} A^{M_1}$ and ${ }_{Z_2} B^{M_2}$.Here,$M_1 
eq M_2$ and $Z_1 
eq Z_2$ $(M = 	ext{atomic weight}, Z = 	ext{atomic number})$.Bu

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isotonic

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(A) Given,${ }_{Z_1} A^{M_1}$ and ${ }_{Z_2} B^{M_2}$.Here,$M_1 
eq M_2$ and $Z_1 
eq Z_2$ $(M = 	ext{atomic weight}, Z = 	ext{atomic number})$.But,$M_1 - Z_1 = M_2 - Z_2$.We know that $	ext{atomic weight} = 	ext{number of protons} + 	ext{number of neutrons}$ and $	ext{atomic number} = 	ext{number of protons}$.Therefore,$	ext{number of neutrons} = 	ext{atomic weight} - 	ext{atomic number}$.Since $M_1 - Z_1$ and $M_2 - Z_2$ represent the number of neutrons in elements $A$ and $B$ respectively,and they are equal,these elements have the same number of neutrons.Species having the same number of neutrons are known as isotones.Thus,these elements are isotonic.

In the two elements,${ }_{Z_1} A^{M_1}$ and ${ }_{Z_2} B^{M_2}$,the following relations are true. $M_1 \neq M_2$ and $Z_1 \neq Z_2$ but $M_1-Z_1=M_2-Z_2$. These elements are ($M$ is atomic weight,$Z$ is atomic number)

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