In the Thorium series,_{90}Th^{232} loses a t | vedclass

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(C) The initial isotope is $_{90}Th^{232}$.Each $\alpha$-particle emission reduces the mass number by $4$ and the atomic number by $2$.Each $\beta$-pa

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$_{82}Pb^{208}$

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(C) The initial isotope is $_{90}Th^{232}$.Each $\alpha$-particle emission reduces the mass number by $4$ and the atomic number by $2$.Each $\beta$-particle emission increases the atomic number by $1$ and leaves the mass number unchanged.Final mass number $= 232 - (6 	imes 4) = 232 - 24 = 208$.Final atomic number $= 90 - (6 	imes 2) + (4 	imes 1) = 90 - 12 + 4 = 82$.The element with atomic number $82$ is Lead $(Pb)$.Therefore,the final isotope is $_{82}Pb^{208}$.

In the Thorium series,$_{90}Th^{232}$ loses a total of $6$ $\alpha$-particles and $4$ $\beta$-particles in ten stages. The final isotope produced in the series is

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