In the reaction given below,the major product | vedclass

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(D) The reactant is $N$-phenyl-isoindolin$-1-$one. The molecule contains two aromatic rings: one fused to the lactam ring and one attached to the nitr

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(D) The reactant is $N$-phenyl-isoindolin$-1-$one. The molecule contains two aromatic rings: one fused to the lactam ring and one attached to the nitrogen atom.The nitrogen atom is attached to the carbonyl group,which is an electron-withdrawing group $(-C=O)$. This makes the nitrogen atom act as an electron-withdrawing group via resonance $(-N-C=O)$,deactivating the $N$-phenyl ring towards electrophilic aromatic substitution.Conversely,the benzene ring fused to the isoindolinone system is less deactivated compared to the $N$-phenyl ring,or rather,the $N$-phenyl ring is significantly deactivated due to the electron-withdrawing effect of the amide nitrogen. However,in this specific structure,the $N$-phenyl ring is more susceptible to electrophilic substitution at the para position due to the lone pair on nitrogen,despite the amide conjugation. Comparing the two rings,the $N$-phenyl ring is more activated towards electrophilic substitution than the ring fused to the carbonyl group.Therefore,electrophilic bromination occurs on the $N$-phenyl ring,primarily at the para position due to steric hindrance at the ortho positions. The major product is the $p$-bromo derivative of the $N$-phenyl group.

In the reaction given below,the major product formed is

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