In the reaction given below:The product 'X' i | vedclass

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(A) $LiAlH_4$ is a strong reducing agent that reduces amides to amines and ketones to secondary alcohols. In the given substrate,the amide group $(-CO

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$A$ structure showing a primary amine and a secondary alcohol group.

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(A) $LiAlH_4$ is a strong reducing agent that reduces amides to amines and ketones to secondary alcohols. In the given substrate,the amide group $(-CONH_2)$ is reduced to a primary amine $(-CH_2NH_2)$ and the ketone group $(>C=O)$ is reduced to a secondary alcohol $(-CH(OH)-)$. The alkene double bond $(C=C)$ remains unaffected by $LiAlH_4$. Therefore,the product '$X$' is the molecule containing both a primary amine and a secondary alcohol group,with the alkene intact.

In the reaction given below:
The product '$X$' is:

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In the reaction given below:The product '$X$' is: