In the reaction,$2n \ R-X \xrightarrow[\text{Dry ether}]{+2n \ Na} \text{product}$. The product obtained is

  • A
    $n \ \text{Alkene}$
  • B
    $n \ \text{Sodium halide}$
  • C
    $n \ \text{Alcohol}$
  • D
    $n \ \text{Alkane}$

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