In the reaction I_2 + 2S_2O_3^{2-} to 2I^{-} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given reaction is: $I_2 + 2S_2O_3^{2-} 	o 2I^{-} + S_4O_6^{2-}$.In this reaction,the oxidation state of iodine changes from $0$ in $I_2$ to $

Vedclass · Accepted Answer

$1/2$ the molecular weight

Vedclass · Answer

(B) The given reaction is: $I_2 + 2S_2O_3^{2-} 	o 2I^{-} + S_4O_6^{2-}$.In this reaction,the oxidation state of iodine changes from $0$ in $I_2$ to $-1$ in $I^{-}$.The change in oxidation state per atom of iodine is $1$. Since there are $2$ atoms of iodine in $I_2$,the total change in oxidation state is $2 	imes 1 = 2$.The $n$-factor for $I_2$ is $2$.The equivalent weight is calculated as: $	ext{Equivalent weight} = \frac{	ext{Molecular weight}}{n	ext{-factor}} = \frac{	ext{Molecular weight}}{2}$.

In the reaction $I_2 + 2S_2O_3^{2-} \to 2I^{-} + S_4O_6^{2-}$,the equivalent weight of iodine will be equal to

Similar Questions

Which of the following is a redox reaction?

Which type of reaction occurs in Kolbe's electrolysis? Why?

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$CuO + H_2 \longrightarrow Cu + H_2O$

How many electrons are needed to reduce $N_2$ to $NH_3$?

In the following reaction,$I_2 + 5Cl_2 + 6H_2O \longrightarrow X + Y$,the products $X$ and $Y$ respectively are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module