In the reaction C_2O_4^{2-} + MnO_4^- + H^{+} | vedclass

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Question

(A) The balanced chemical equation is $5C_2O_4^{2-} + 2MnO_4^- + 16H^{+} 	o 2Mn^{2+} + 10CO_2 + 8H_2O$. In this reaction,the oxidation state of carbo

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$C_2O_4^{2-}$

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(A) The balanced chemical equation is $5C_2O_4^{2-} + 2MnO_4^- + 16H^{+} 	o 2Mn^{2+} + 10CO_2 + 8H_2O$. In this reaction,the oxidation state of carbon in $C_2O_4^{2-}$ increases from $+3$ to $+4$ (oxidation). The oxidation state of manganese in $MnO_4^-$ decreases from $+7$ to $+2$ (reduction). Since $C_2O_4^{2-}$ undergoes oxidation,it acts as the reducing agent (reductant).

In the reaction $C_2O_4^{2-} + MnO_4^- + H^{+} \to Mn^{2+} + CO_2 + H_2O$,the reductant is:

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