In the reaction $2Na_2S_2O_3 + I_2 \to Na_2S_4O_6 + 2NaI$,the equivalent weight of $Na_2S_2O_3$ (molecular weight = $M$) is equal to:

  • A
    $M$
  • B
    $M/2$
  • C
    $M/3$
  • D
    $M/4$

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