In the number 7524693,how many digits will re | vedclass

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(B) Original number: $7, 5, 2, 4, 6, 9, 3$Positions: $1, 2, 3, 4, 5, 6, 7$Arranging the digits in ascending order:Sorted digits: $2, 3, 4, 5, 6, 7, 9$

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(B) Original number: $7, 5, 2, 4, 6, 9, 3$Positions: $1, 2, 3, 4, 5, 6, 7$Arranging the digits in ascending order:Sorted digits: $2, 3, 4, 5, 6, 7, 9$Positions: $1, 2, 3, 4, 5, 6, 7$Comparing the positions:Original: $7, 5, 2, 4, 6, 9, 3$Sorted: $2, 3, 4, 5, 6, 7, 9$Comparing digit by digit:Position $1: 7 
eq 2$Position $2: 5 
eq 3$Position $3: 2 
eq 4$Position $4: 4 
eq 5$Position $5: 6 = 6$Position $6: 9 
eq 7$Position $7: 3 
eq 9$Only the digit $6$ remains in the same position. Therefore,there is only one such digit.

In the number $7524693$,how many digits will remain at the same position from the beginning if the digits are arranged in ascending order?

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