In the nuclear reaction,{ }_6^{11} C rightarr | vedclass

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(C) The given nuclear reaction is: ${ }_6^{11} C \rightarrow{ }_5^{11} B + \beta^+ + X$ ...$(i)$In $\beta^+$ decay (positron emission),a proton inside

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a neutrino

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(C) The given nuclear reaction is: ${ }_6^{11} C ightarrow{ }_5^{11} B + \beta^+ + X$ ...$(i)$In $\beta^+$ decay (positron emission),a proton inside the nucleus is converted into a neutron,a positron,and a neutrino.The reaction is represented as: $p ightarrow n + \beta^+ + 
u$.The conservation of lepton number requires the emission of a neutrino $(u)$ along with the positron to balance the lepton number.Therefore,in the decay of ${ }_6^{11} C$,the particle $X$ is a neutrino $(u)$.

In the nuclear reaction,${ }_6^{11} C \rightarrow{ }_5^{11} B + \beta^+ + X$,$X$ stands for

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