In the non-relativistic regime,if the momentu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The kinetic energy $K$ is related to momentum $p$ by the formula $K = \frac{p^2}{2m}$.Since mass $m$ is constant,we have $K \propto p^2$.Let the i

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(C) The kinetic energy $K$ is related to momentum $p$ by the formula $K = \frac{p^2}{2m}$.Since mass $m$ is constant,we have $K \propto p^2$.Let the initial momentum be $p_1 = p$ and the final momentum be $p_2 = p + 100\% 	ext{ of } p = 2p$.The ratio of kinetic energies is $\frac{K_2}{K_1} = \left(\frac{p_2}{p_1}ight)^2 = \left(\frac{2p}{p}ight)^2 = 4$.Thus,$K_2 = 4K_1$.The percentage increase in kinetic energy is given by $\frac{K_2 - K_1}{K_1} 	imes 100\% = \frac{4K_1 - K_1}{K_1} 	imes 100\% = 300\%$.

In the non-relativistic regime,if the momentum is increased by $100\%$,the percentage increase in kinetic energy is (in $\%$)

Similar Questions

Two bodies of masses $m$ and $4m$ are moving with equal kinetic energy $(K.E.)$. The ratio of their linear momentums is

$A$ graph between kinetic energy $K$ and momentum $P$ of a particle is plotted as shown in the figure. The mass of the moving particle is ........ $kg$.

What is the kinetic energy in Joules of a bullet of mass $2 \, g$ moving with a velocity of $500 \, m/s$ (in $, J$)?

Two bodies of masses $m_1$ and $m_2$ have equal kinetic energies. If $p_1$ and $p_2$ are their respective momenta,then the ratio $p_1:p_2$ is equal to

When the mass and speed of the body are doubled,the kinetic energy of the body

Vedclass Test Series

Exam Paper Generator

Online Exam Module