(B) The reaction between concentrated $H_2SO_4$ and $HNO_3$ is as follows:$HNO_3 + 2H_2SO_4 \rightleftarrows NO_2^+ + H_3O^+ + 2HSO_4^-$Here,$NO_2^+$

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(B) The reaction between concentrated $H_2SO_4$ and $HNO_3$ is as follows:$HNO_3 + 2H_2SO_4 \rightleftarrows NO_2^+ + H_3O^+ + 2HSO_4^-$Here,$NO_2^+$ is the nitronium ion,which acts as the electrophile or the active nitrating species in the nitration reaction.