In the logic circuit given,A, B and C are the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given circuit consists of a $NOR$ gate followed by an $AND$ gate.Inputs $B$ and $C$ are fed into a $NOR$ gate,which produces an output $X = \o

Vedclass · Accepted Answer

when $A=1, B=0, C=0$.

Vedclass · Answer

(C) The given circuit consists of a $NOR$ gate followed by an $AND$ gate.Inputs $B$ and $C$ are fed into a $NOR$ gate,which produces an output $X = \overline{B+C}$.This output $X$ and input $A$ are then fed into an $AND$ gate to produce the final output $Y$.Therefore,the Boolean expression for the output is $Y = A \cdot X = A \cdot (\overline{B+C})$.For the output $Y$ to be $HIGH$ $(Y=1)$,both $A$ must be $1$ and $(\overline{B+C})$ must be $1$.$(\overline{B+C}) = 1$ only when $B+C = 0$,which means $B=0$ and $C=0$.Thus,$Y=1$ when $A=1, B=0, C=0$.

In the logic circuit given,$A, B$ and $C$ are the inputs and $Y$ is the output. The output $Y$ is $HIGH$ when:

Similar Questions

The logic gate represented by the following logic circuit is

Which one of the following logic gates is called a Universal gate?

The figure shows a system of logic gates. From the study of the truth table,it can be found that to produce a high output $(1)$ at $R$,we must have

The following figure shows a logic gate circuit with two inputs $A$ and $B$ and the output $Y$. The voltage waveforms of $A$,$B$,and $Y$ are as given. The logic gate is:

For the following digital logic circuit,the correct truth-table is

Vedclass Test Series

Exam Paper Generator

Online Exam Module