In the Lassaigne sodium fusion test,$N$ and $S$ of an organic compound are converted into:

  • A
    $NaCN$ and $Na_2S$
  • B
    $Na_2S$ and $NaCNS$
  • C
    $NaCN$ and $NaCNS$
  • D
    $NaCN$,$Na_2S$ and $NaCNS$

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Similar Questions

Given below are two statements :
Statement $I :$ In Lassaigne's test,the covalent organic molecules are transformed into ionic compounds.
Statement $II :$ The sodium fusion extract of an organic compound having $N$ and $S$ gives prussian blue colour with $FeSO_4$ and $FeCl_3$.
In the light of the above statements,choose the correct answer from the options given below.

An organic compound containing phosphorus on oxidation with $Na_2O_2$ gives a compound '$X$'. This '$X$' when boiled with $HNO_3$ followed by treatment with ammonium molybdate reagent gives a yellow precipitate '$Y$'. '$X$' and '$Y$' respectively are:

Match the compounds in List-$I$ with the observations in List-$II$,and choose the correct option.
List-$I$ List-$II$
$I$. Aniline $P$. Sodium fusion extract of the compound on boiling with $FeSO_4$,followed by acidification with conc. $H_2SO_4$,gives Prussian blue color.
$II$. $o$-Cresol $Q$. Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
$III$. Cysteine $R$. Addition of the compound to a saturated solution of $NaHCO_3$ results in effervescence.
$IV$. Caprolactam $S$. The compound reacts with bromine water to give a white precipitate.
$T$. Treating the compound with neutral $FeCl_3$ solution produces violet color.

The formulae of ammonium phosphomolybdate $(X)$ and the compound $(Y)$ responsible for Prussian blue colour are:

The presence of halogen in an organic compound is detected by:

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