In the hydrogen spectrum,the ratio of the wavelengths for Lyman-alpha radiation to Balmer-alpha radiation is

  • A
    $5 / 27$
  • B
    $5 / 48$
  • C
    $27 / 5$
  • D
    $1 / 3$

Explore More

Similar Questions

The ratio of maximum to minimum wavelength in the Balmer series of a hydrogen atom is

Which of the following statement$(s)$ is(are) correct about the spectrum of hydrogen atom?
$(A)$ The ratio of the longest wavelength to the shortest wavelength in Balmer series is $9/5$.
$(B)$ There is an overlap between the wavelength ranges of Balmer and Paschen series.
$(C)$ The wavelengths of Lyman series are given by $\lambda = \frac{\lambda_0}{1 - 1/m^2}$,where $\lambda_0$ is the shortest wavelength of Lyman series and $m$ is an integer.
$(D)$ The wavelength ranges of Lyman and Balmer series do not overlap.

The wavelength of the first line of the Balmer series is $6563 \; Å$. The Rydberg constant for hydrogen is about

The wavelength of radiation emitted is ${\lambda _0}$ when an electron jumps from the third to the second orbit of a hydrogen atom. For the electron jump from the fourth to the second orbit of the hydrogen atom,the wavelength of radiation emitted will be

Difficult
View Solution

Number of visible lines in Balmer's series

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo