In the $Hofmann$ bromamide degradation reaction,the number of moles of $NaOH$ and $Br_2$ used per mole of amine produced are:

• A
  $Two$ moles of $NaOH$ and $two$ moles of $Br_2$.
• B
  $Four$ moles of $NaOH$ and $one$ mole of $Br_2$.
• C
  $One$ mole of $NaOH$ and $one$ mole of $Br_2$.
• D
  $Four$ moles of $NaOH$ and $two$ moles of $Br_2$.