In the ground state of atomic Fe ,(Z = 26),th | vedclass

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(B) The electronic configuration of $Fe$ $(Z = 26)$ is $[Ar] 3d^6 4s^2$.In the $3d$ subshell,there are $6$ electrons. According to Hund's rule,the dis

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$49$

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(B) The electronic configuration of $Fe$ $(Z = 26)$ is $[Ar] 3d^6 4s^2$.In the $3d$ subshell,there are $6$ electrons. According to Hund's rule,the distribution is:						$\uparrow \downarrow$			$\uparrow$			$\uparrow$			$\uparrow$			$\uparrow$			Number of unpaired electrons $(n) = 4$.The spin-only magnetic moment $(\mu)$ is given by the formula $\mu = \sqrt{n(n + 2)} \,BM$.$\mu = \sqrt{4(4 + 2)} = \sqrt{24} \,BM$.Using $\sqrt{24} \approx 4.899 \,BM$.$\mu = 48.99 	imes 10^{-1} \,BM$.Rounding off to the nearest integer,we get $49$.

In the ground state of atomic $Fe \,(Z = 26)$,the spin-only magnetic moment is ...... $\times 10^{-1} \,BM$. (Round off to the nearest integer).
$[$Given $: \sqrt{3} = 1.73, \sqrt{2} = 1.41]$

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In the ground state of atomic $Fe \,(Z = 26)$,the spin-only magnetic moment is ...... $\times 10^{-1} \,BM$. (Round off to the nearest integer).$[$Given $: \sqrt{3} = 1.73, \sqrt{2} = 1.41]$