In the given transformation,which of the foll | vedclass

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(A) The given transformation involves the reduction of a ketone group to a methylene group ($-COCH_3$ to $-CH_2CH_3$) while keeping the double bond an

Vedclass · Accepted Answer

$NH_2NH_2, \, 	ext{OH}^-$

Vedclass · Answer

(A) The given transformation involves the reduction of a ketone group to a methylene group ($-COCH_3$ to $-CH_2CH_3$) while keeping the double bond and the hydroxyl group intact.$1$. $NH_2NH_2, 	ext{OH}^-$ (Wolff-Kishner reduction) is a basic condition that reduces the carbonyl group to a methylene group without affecting the double bond or the alcohol group.$2$. $Zn-Hg/HCl$ (Clemmensen reduction) is an acidic condition. The $HCl$ present would react with the alcohol group to form an alkyl chloride and might also affect the double bond.$3$. $Na, 	ext{Liq. } NH_3$ (Birch reduction or dissolving metal reduction) would likely reduce the carbon-carbon double bond.$4$. $NaBH_4$ reduces ketones to alcohols,not to methylene groups.Therefore,the Wolff-Kishner reduction is the most appropriate reagent.

In the given transformation,which of the following is the most appropriate reagent?

Similar Questions

What is the possible product $(P)$ in the following reaction?

The products $(A)$ and $(B)$ respectively in the above Beckmann rearrangement reactions are:

$\text{Phthalic anhydride}$ $\xrightarrow {PCl_5} A$ $\xrightarrow {LiAlH_4} B$ $\xrightarrow {PCC} C$ $\xrightarrow [\Delta ] {OH^{-}} D$
Compound $D$ is :-

In the reaction
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Product $Z$ is

The smallest ketone and its next homologue are reacted with $NH_2OH$ to form oximes.

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