In the given reaction sequence,the major product $C$ is ..... .

Alkyl halide $\xrightarrow[\text{Ether}]{Mg}$ Grignard Reagent $\xrightarrow{H_2O}$ Propane,then alkyl halide may be :-

Match the type of reaction given in Column-$I$ with the reaction in Column-$II$.

Column-$I$ (Reactants)	Column-$II$ (Type of Reaction)
$(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$	$(i)$ Wurtz-Fittig reaction
$(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$	$(ii)$ Diazotization
$(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$	$(iii)$ Sandmeyer reaction
$(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$	$(iv)$ Fittig reaction

Match the reactions given in Column-$I$ with the names given in Column-$II$.

Consider the following $E_1/S_N1$ reaction. The missing product$(s)$ is(are):

Correct statements regarding alkyl halides ($R-X$) among the following are: A. Alcohol being less polar solvent as compared to water, alcoholic $KOH$ favours elimination reaction with $R-X$. B. Order of reactivity towards $S_N1$ mechanism is $C_6H_5-CH_2-Cl > C_6H_5-CHCl-C_6H_5$. C. Non substituted aryl halides exhibit properties similar to alkyl halides. D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne. E. $R-Cl$ can be prepared by reacting $R-OH$ with $SOCl_2$ but $Ar-Cl$ cannot be prepared by reacting $Ar-OH$ with $SOCl_2$. Choose the correct answer from the options given below: