In the given reaction $C_6H_5CHO + X \xrightarrow{(i) Zn, (ii) HOH/NH_4Cl} C_6H_5-CH(OH)-CH_2-COOC_2H_5$,$[X]$ will be:
- A$CH_3-COOC_2H_5$
- B$CH_3-CH_2-COOC_2H_5$
- C$Br-CH_2-COOC_2H_5$
- D$Br_2CH-COOC_2H_5$
Explore More
Similar Questions
The rate of hydrate formation for the given compounds is:
Medium
View Solution$HOCH_2-C(=O)-CH(OH)-CH_2OH \xrightarrow{HIO_4}$ Product obtained is:
Difficult
View SolutionWhat is the product '$X$' in the following reaction?
(Image of $3-$formylcyclohexanone reacting with $[Ag(NH_3)_2]^+$)
(Image of $3-$formylcyclohexanone reacting with $[Ag(NH_3)_2]^+$)
Difficult
View SolutionAmong the aromatic isomers with the molecular formula $C_8H_8O$,one isomer $X$ gives the iodoform test,while another isomer $Y$ gives the Benedict's test. What are the structures of $X$ and $Y$ respectively?
Which product is obtained when cyclopentanone reacts with hydroxylamine in an acidic medium?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo