In the given reaction,the products are:

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Question

(A) The reactant is a secondary alkyl halide ($2$-bromotetralin). The reagent used is $CH_3-C \equiv CNa$,which is a strong nucleophile and a strong b

Vedclass · Accepted Answer

$20$% substitution product and $80$% elimination product

Vedclass · Answer

(A) The reactant is a secondary alkyl halide ($2$-bromotetralin). The reagent used is $CH_3-C \equiv CNa$,which is a strong nucleophile and a strong base. In the presence of a strong base and a secondary alkyl halide,the elimination reaction $(E2)$ is highly favored over the substitution reaction $(S_N2)$ due to steric hindrance. Therefore,the major product formed is the elimination product (alkene),while the substitution product is formed in a minor amount. Experimental results for this specific reaction show that the elimination product is the major product ($80\%$ or more),and the substitution product is the minor product ($20\%$ or less). Thus,the correct representation is $20\%$ substitution product and $80\%$ elimination product.

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