In the given reaction cycle,X,Y and Z respect | vedclass

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(C) The reaction between $CaCl_2$ and $Na_2CO_3$ is a double displacement reaction:$CaCl_2 + Na_2CO_3 \rightarrow CaCO_3(s) + 2NaCl(aq)$Comparing this

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$CaCO_3, NaCl, HCl$

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(C) The reaction between $CaCl_2$ and $Na_2CO_3$ is a double displacement reaction:$CaCl_2 + Na_2CO_3 \rightarrow CaCO_3(s) + 2NaCl(aq)$Comparing this with the given reaction $CaCl_2 + Na_2CO_3 \rightarrow X + Y$,we identify $X$ as $CaCO_3$ and $Y$ as $NaCl$.To convert $CaCO_3$ back to $CaCl_2$,it is reacted with hydrochloric acid $(HCl)$:$CaCO_3 + 2HCl \rightarrow CaCl_2 + H_2O + CO_2$Thus,$Z$ is $HCl$.Therefore,$X = CaCO_3$,$Y = NaCl$,and $Z = HCl$.

In the given reaction cycle,$X$,$Y$ and $Z$ respectively are:
$CaCl_2 + Na_2CO_3 \rightarrow X + Y$
$X \xrightarrow{Z} CaCl_2$

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In the given reaction cycle,$X$,$Y$ and $Z$ respectively are:$CaCl_2 + Na_2CO_3 \rightarrow X + Y$$X \xrightarrow{Z} CaCl_2$