In the given reaction,X + Y + 3 Z rightleftha | vedclass

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(D) The balanced chemical equation is: $X + Y + 3 Z \rightarrow XYZ_3$.Initial moles: $X = 1 \ mol$,$Y = 1 \ mol$,$Z = 0.05 \ mol$.To find the Limitin

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(D) The balanced chemical equation is: $X + Y + 3 Z ightarrow XYZ_3$.Initial moles: $X = 1 \ mol$,$Y = 1 \ mol$,$Z = 0.05 \ mol$.To find the Limiting Reagent ($L$.$R$.),divide the moles by their stoichiometric coefficients:$X: 1/1 = 1$$Y: 1/1 = 1$$Z: 0.05/3 \approx 0.0167$Since $Z$ has the smallest ratio,$Z$ is the Limiting Reagent.Moles of $XYZ_3$ formed = $\frac{1}{3} 	imes 	ext{moles of } Z = \frac{0.05}{3} \ mol$.Molar mass of $XYZ_3 = 10 + 20 + (3 	imes 30) = 120 \ g/mol$.Yield of $XYZ_3 = \frac{0.05}{3} 	imes 120 = 0.05 	imes 40 = 2 \ g$.

In the given reaction,$X + Y + 3 Z \rightleftharpoons XYZ_3$. If one mole of each of $X$ and $Y$ with $0.05 \ mol$ of $Z$ reacts to form the compound $XYZ_3$,calculate the yield of $XYZ_3$ in grams. (Given: Atomic masses of $X, Y$ and $Z$ are $10, 20$ and $30 \ amu$,respectively). (Nearest integer)

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