In the given reaction,X will be:Cyclohexene x | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction proceeds as follows:$1$. Cyclohexene reacts with $NBS$ ($N$-Bromosuccinimide) to undergo allylic bromination,forming $3$-bromocyclohe

Vedclass · Accepted Answer

Cyclohex$-2-$ene$-1-$carboxylic acid

Vedclass · Answer

(D) The reaction proceeds as follows:$1$. Cyclohexene reacts with $NBS$ ($N$-Bromosuccinimide) to undergo allylic bromination,forming $3$-bromocyclohexene.$2$. $3$-bromocyclohexene reacts with $Mg$ in the presence of ether to form the Grignard reagent,$3$-cyclohexenylmagnesium bromide.$3$. The Grignard reagent then reacts with $CO_2$ followed by acidic workup $(H^+)$ to form the carboxylic acid,cyclohex$-2-$ene$-1-$carboxylic acid.Thus,the final product $X$ is cyclohex$-2-$ene$-1-$carboxylic acid.

In the given reaction,$X$ will be:
Cyclohexene $\xrightarrow{NBS}$ $\xrightarrow[ether]{Mg}$ $\xrightarrow[2.H^{+}]{1.CO_2} X$

Similar Questions

In which of the following species,addition of $H^{+}$ will be faster in comparison to other three species?

Identify the product of the following reaction: $CH_3-CH=CH-CH_3 \xrightarrow[(ii) H_2O, Zn]{(i) O_3} \text{Product}$

$CH_3-CH=CH_2 + HBr \xrightarrow{\ \ } .........$,the product formed is

Which of the following compounds was the starting material for the oxidation shown below?
$Compound \xrightarrow{KMnO_4 / H^{\oplus}} \text{Product}$

Oxymercuration-demercuration of allylbenzene $(C_6H_5CH_2CH=CH_2)$ produces:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the given reaction,$X$ will be:Cyclohexene $\xrightarrow{NBS}$ $\xrightarrow[ether]{Mg}$ $\xrightarrow[2.H^{+}]{1.CO_2} X$