In the given reaction,Ph-C equiv C-CH_3 xrigh | vedclass

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(C) The reaction of an alkyne with $H^{+}/Hg^{2+}$ (mercuric sulfate in dilute sulfuric acid) is a hydration reaction that follows Markovnikov's rule.

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$Ph-CO-CH_2CH_3$

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(C) The reaction of an alkyne with $H^{+}/Hg^{2+}$ (mercuric sulfate in dilute sulfuric acid) is a hydration reaction that follows Markovnikov's rule.$Ph-C \equiv C-CH_3 + H_2O \xrightarrow{H^{+}/Hg^{2+}} Ph-C(OH)=CH-CH_3$ (enol intermediate).The enol intermediate undergoes tautomerization to form the more stable ketone.$Ph-C(OH)=CH-CH_3 \rightleftharpoons Ph-CO-CH_2CH_3$ (propiophenone).Thus,the final product $A$ is $Ph-CO-CH_2CH_3$.

In the given reaction,
$Ph-C \equiv C-CH_3 \xrightarrow{H^{+}/Hg^{2+}} A$
the product $A$ is

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In the given reaction,$Ph-C \equiv C-CH_3 \xrightarrow{H^{+}/Hg^{2+}} A$the product $A$ is