Acetylene gas when passed through 20% H_2SO_ | vedclass

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(B) The hydration of acetylene $(CH \equiv CH)$ to form acetaldehyde $(CH_3CHO)$ is a classic reaction known as Kucherov's reaction.This reaction requ

Vedclass · Accepted Answer

$HgSO_4$

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(B) The hydration of acetylene $(CH \equiv CH)$ to form acetaldehyde $(CH_3CHO)$ is a classic reaction known as Kucherov's reaction.This reaction requires the presence of dilute $H_2SO_4$ and a mercuric salt catalyst,typically $HgSO_4$.The reaction proceeds as follows:$CH \equiv CH + H_2O$ $\xrightarrow{H_2SO_4, HgSO_4} [CH_2=CHOH]$ $\rightarrow CH_3CHO$Therefore,the correct catalyst is $HgSO_4$.

Acetylene gas when passed through $20\% \ H_2SO_4$ at $80 \, ^\circ C$ gives acetaldehyde. The catalyst required for this conversion is:

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