In the given network, the potential differenc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The circuit consists of two parallel branches connected between points $A$ and $C$. The total current $I = 4 \, A$ enters at $A$.Branch $1$ (upper

Vedclass · Accepted Answer

$-\frac{10}{3} \, V$

Vedclass · Answer

(A) The circuit consists of two parallel branches connected between points $A$ and $C$. The total current $I = 4 \, A$ enters at $A$.Branch $1$ (upper) has resistors $2 \, \Omega$ and $3 \, \Omega$ in series, so $R_1 = 2 + 3 = 5 \, \Omega$.Branch $2$ (lower) has resistors $5 \, \Omega$ and $20 \, \Omega$ in series, so $R_2 = 5 + 20 = 25 \, \Omega$.The current $I_1$ in the upper branch is $I_1 = I \cdot \frac{R_2}{R_1 + R_2} = 4 \cdot \frac{25}{5 + 25} = 4 \cdot \frac{25}{30} = \frac{10}{3} \, A$.The current $I_2$ in the lower branch is $I_2 = I \cdot \frac{R_1}{R_1 + R_2} = 4 \cdot \frac{5}{5 + 25} = 4 \cdot \frac{5}{30} = \frac{2}{3} \, A$.Let $V_A = 0 \, V$. Then $V_B = V_A - I_1 \cdot 2 = 0 - (\frac{10}{3}) \cdot 2 = -\frac{20}{3} \, V$.$V_D = V_A - I_2 \cdot 5 = 0 - (\frac{2}{3}) \cdot 5 = -\frac{10}{3} \, V$.The potential difference $V_B - V_D = -\frac{20}{3} - (-\frac{10}{3}) = -\frac{10}{3} \, V$.

In the given network, the potential difference between the points $B$ and $D$ is

Similar Questions

In the circuit shown,the resistance $r$ is a variable resistance. If for $r = fR$,the heat generation in $r$ is maximum,then the value of $f$ is:

What is the effective resistance between $A$ and $B$ for the given infinite resistor network?

In the network shown in the figure,the potential difference across the $2R$ resistor is...... (The cell has an $emf$ $E$ and no internal resistance).

What is the reading of the voltmeter in the following figure (in $V$)?

Consider the four circuits shown in the figure given below. In which circuit is the power dissipated the greatest? (Neglect the internal resistance of the power supply)

Vedclass Test Series

Exam Paper Generator

Online Exam Module