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(D) The circuit consists of two batteries connected in opposition and a resistor in series.The equivalent electromotive force $(V_{eq})$ of the circui

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$5$

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(D) The circuit consists of two batteries connected in opposition and a resistor in series.The equivalent electromotive force $(V_{eq})$ of the circuit is the difference between the two voltages because they are connected in opposition:$V_{eq} = 100 \ V - 5 \ V = 95 \ V$The total resistance $(R)$ in the circuit is $19 \ \Omega$.Using Ohm's law,the current $(I)$ flowing through the circuit is given by:$I = \frac{V_{eq}}{R}$$I = \frac{95 \ V}{19 \ \Omega} = 5 \ A$Therefore,the current flowing through the circuit is $5 \ A$.

In the given circuit,the current flowing through the circuit is: (in $A$)

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