In the given circuit,find the current in each | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let us analyze the potential at different points in the circuit.Starting from the leftmost wire,let the potential be $0 	ext{ V}$.Moving across t

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) Let us analyze the potential at different points in the circuit.Starting from the leftmost wire,let the potential be $0 	ext{ V}$.Moving across the top branch,the potential changes by $2 	ext{ V}$ at each battery. Similarly,for the bottom branch,the potential changes by $2 	ext{ V}$ at each battery.For the first vertical resistor of $1 \Omega$,the potential at the top node is $0 	ext{ V} - 2 	ext{ V} = -2 	ext{ V}$ and at the bottom node is $0 	ext{ V} - 2 	ext{ V} = -2 	ext{ V}$.The potential difference across this resistor is $(-2 	ext{ V}) - (-2 	ext{ V}) = 0 	ext{ V}$.Similarly,for the second vertical resistor,the potential at the top node is $-2 	ext{ V} - 2 	ext{ V} = -4 	ext{ V}$ and at the bottom node is $-2 	ext{ V} - 2 	ext{ V} = -4 	ext{ V}$.The potential difference is $(-4 	ext{ V}) - (-4 	ext{ V}) = 0 	ext{ V}$.For the third resistor,the potential at the top node is $-4 	ext{ V} - 2 	ext{ V} = -6 	ext{ V}$ and at the bottom node is $-4 	ext{ V} - 2 	ext{ V} = -6 	ext{ V}$.The potential difference is $(-6 	ext{ V}) - (-6 	ext{ V}) = 0 	ext{ V}$.Since the potential difference across each resistor is $0 	ext{ V}$,the current flowing through each resistor is $I = V/R = 0 	ext{ V} / 1 \Omega = 0 	ext{ A}$.

In the given circuit,find the current in each resistance. (in $A$)

Similar Questions

The reading of the ideal voltmeter in the adjoining diagram will be ................. $V$.

Twelve wires each having resistance $2 \Omega$ are joined to form a cube. $A$ battery of $6 \text{ V}$ emf is connected across points $a$ and $c$. The voltage difference between $e$ and $f$ is . . . . . . $\text{V}$.

Two resistors of $100 \Omega$ each are connected in series with a $9 \text{ V}$ battery. $A$ voltmeter of $400 \Omega$ resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is . . . . . . $V$.

The potential difference between points $A$ and $B$ of the adjoining figure is

Vedclass Test Series

Exam Paper Generator

Online Exam Module